2y^2-5/4y=1/2

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Solution for 2y^2-5/4y=1/2 equation:


y in (-oo:+oo)

2*y^2-((5/4)*y) = 1/2 // - 1/2

2*y^2-((5/4)*y)-(1/2) = 0

2*y^2+(-5/4)*y-1/2 = 0

2*y^2-5/4*y-1/2 = 0

DELTA = (-5/4)^2-(-1/2*2*4)

DELTA = 89/16

DELTA > 0

y = ((89/16)^(1/2)+5/4)/(2*2) or y = (5/4-(89/16)^(1/2))/(2*2)

y = ((89/16)^(1/2)+5/4)/4 or y = (5/4-(89/16)^(1/2))/4

y in { (5/4-(89/16)^(1/2))/4, ((89/16)^(1/2)+5/4)/4 }

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